![]() there is no potential difference across due to, and current preferentially flows (counter-clockwise) through the short. Solutionįirst, removing, the short means that the potential must be the same on either side of -i.e. Add the results of both calculations and use currents through each component to determine the power supplied/dissipated by each. Remove each voltage source in turn and determine the voltage across and current through the three remaining components. (Figure 7.2.1) Figure 7.2.1 A DC resistive network. Circuit analysis by superposition therefore follows a process of replacing all voltage sources but one within a network with short circuits, then using the summation rules of series-parallel combinations of resistors described in Resistors in Series and Parallel and determining the voltage across and current in each branch due to the remaining voltage source, and then repeating this process for all voltage sources and superposing the results.Ĭalculating Current Using Superposition Theoremįind the power supplied by the voltage sources and the power dissipated by the resistors in Figure 7.2.1, using the superposition approach. Similarly, superposition theorem tells us that the voltage across any branch of a circuit can be broken up as a linear combination of potential differences due to each voltage source in a resistive network, considered individually. Mesh Analysis makes use of linearity in its assumption that the current through any branch can be broken down into “parts”, the summation of which is the actual current through the branch. The linearity of resistive networks that satisfy Ohm’s law allows a number of simplifying approaches to be taken in their analysis.
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